Showing posts with label strong acid. Show all posts
Showing posts with label strong acid. Show all posts

Sunday, October 17, 2010

Strong Acids and Bases: Names and Formulas




The STRONG ACIDS are:

Hydrochloric acid: HCl
Hydrobromic acid: HBr
Hydroiodic acid: HI
Sulfuric acid: H2SO4
Nitric acid: HNO3
Perchloric acid: HClO4

The STRONG BASES are:

Lithium hydroxide: LiOH
Sodium hydroxide: NaOH
Potassium hydroxide: KOH
Calcium hydroxide: Ca(OH)2
Strontium hydroxide: Sr(OH)2
Barium hydroxide: Ba(OH)2

Friday, October 15, 2010

16.7: Acid-Base Titration Curves

Acid-Base Titrations:

An acid-base titration is a procedure for determining the amount of acid (or base) in a solution by determining the volume of base (or acid) of known concentration that will completely react with it.

Can titrate:
1) A strong acid with a strong base
2) A strong acid with a weak base
3) A weak acid with a strong base
4) A weak acid with a weak base → this kind of titration will not be on the exam.

An acid-base titration curve is a plot of the pH of a solution of acid (or base) against the volume of added base (or acid). Here is one for a strong acid titrated with a strong base:




The change in pH as the base is added will be slow at first, then it will reach a point where the pH increases drastically before leveling out again.

The middle of this rapid incline is called the equivalence point: the point in a titration when the smallest amount of titrant has been added that is sufficient to fully neutralize or react with the acid or base (the point when all the acid and base have reacted).

Example:

The case of a strong acid and a strong base:

Note: The pH at the equivalence point for a strong acid and a strong base will always be 7.

What is the pH when 27.0mL of 0.450 M HCl is titrated (read as mixed!) with 45.0mL of 0.500 M NaOH?

Remember with mixing/titrating, the first thing we do is convert to moles:

mols HCl = (0.0270 L)(0.450 mols/L) = 0.0122 mol HCl
mols NaOH = (0.0450 L)(0.500 mols/L) = 0.0225 mol NaOH

The acid and base react to form a salt:

HCl (aq) + NaOH (aq) → H2O (l) + NaCl (aq)



Convert to concentration by dividing by new volume:

NaOH = (0.0103 mol) / (0.072 L) = 0.143 M NaOH = 0.143 M OH-
pOH = -log(0.143) = 0.844
pH = 14 – pOH = 13.2

Example:

The case of a strong acid and a weak base:


What is the pH at the equivalence point when 0.150 M of HCl titrates 20 mL of 0.200 M NH3?

Remember that at the equivalence point, mols of HCl = mols of NH3.

Since we're dealing with a titration, first convert to mols:

mols NH3= (0.200 mols/L)(0.0200 L) = 4.00 x 10-3 mols NH3
and mols NH3 = mols HCl = 4.00 x 10-3 mols

To get the final volume after titration, we'll need to know the volume of HCl. Since we know the mols and molarity, we can use what we know to find the volume.

Concentration = Mols x Volume,
Volume = Mols / Concentration

Volume HCl = (4.00 x 10-3 mols) / (0.150 M) = 0.0267 L HCl
So total volume of titration is 0.0267L + 0.0200 L = 0.0467 L
Concentrations of HCl and NH3 = (4.00 x 10-3 mols) / (0.0467 L) = 0.0857 M

So 0.0857 M of the acid and 0.0857 M of the base react to form 0.0857 M of a salt:

HCl + NH3 → NH4Cl

NH4Cl dissociates in water and leaves NH4+ and Cl- ions. Cl- ions form a strong acid which dissociates 100% in water, so no reaction there. When NH4+ ions react with water:

NH4+ (aq) + H2O (l) ⇌ H3O+ (aq) + NH3 (aq)



Ka = (x2) / (0.0857 – x) → approximation holds
Ka= (x2) / (0.0857)

We need to find the Ka for NH4+, so first find Kb of the conjugate base, NH3, and plug it in:

Ka = Kw / Kb

Kb for NH3 = 1.8 x 10-5
Ka for NH4+= (1 x 10-14) / (1.8 x 10-5) = 5.56 x 10-10

5.56 x 10-10 = (x2) / (0.0857)
x = 6.9 x 10-6 = [H3O+]
pH = -log(6.9 x 10-6) = 5.16

Example:

The case of a weak acid and a strong base:

What is the pH when 35.0mL of 0.215 M HClO is titrated by 0.400 M LiOH to the equivalence point?

Remember that at equivalence, mols HClO = mols LiOH.

And since we're titrating, remember the first thing to do is convert to mols:

mols HClO = (0.350 L)(0.215 mols/L) = 0.00753 mols HClO
and mols HClO = mols LiOH = 0.00753 mols

To get the final volume after titration, we'll need to know the volume of LiOH. Since we know the mols and molarity, we can use what we know to find the volume.

Concentration = Mols x Volume,
Volume = Mols / Concentration

Volume LiOH = ( 0.00753 mols) / (0.400 M) = 0.0188 L LiOH
So total volume of titration is 0.0350L + 0.0188 L = 0.0538 L
Concentrations of HClO and LiOH = (0.00753 mols) / (0.0538 L) = 0.140 M

So 0.140 M of the acid and 0.140 M of the base react to form 0.140 M of a salt:

HClO + LiOH → LiClO

LiClO dissociates in water and leaves Li+ and ClO- ions. Li+ ions form a strong base which dissociates 100% in water, so no reaction there. When ClO- ions react with water:

ClO- (aq) + H2O (l) ⇌ HClO (aq) + OH- (aq)



Kb = (x2) / (0.140 – x) → approximation holds
Kb = (x2) / (0.140)

We need to find the Kb for ClO-, so first find Ka of the acid, HClO, and plug it in:

Kb = Kw / Ka

Ka for HClO = 3.5 x 10-8
Kb for ClO- = (1 x 10-14) / (3.5 x 10-8) = 2.86 x 10-7

2.86 x 10-7 = (x2) / (0.140)
x = 2.00 x 10-4 = [OH-]
pOH = -log(2.00 x 10-4) = 3.7
pH = 14 – 3.7 = 10.3

Monday, September 20, 2010

15.1-15.8: All of Chapter 15

Strong Acids and Bases:



(If it is an acid or a base and it is not in this table, then it is a weak acid or base. An indicator that something is an acid is that it will start with a hydrogen, ex: H3PO3, H3PO4).

Three Definitions:

1. Arrhenius Concept of Acids and Bases:

-Acid: a substance that, when dissolved in water, increases the concentration of hydronium ion, H3O+ (aq). H+ (aq) is interchangeable with H3O+ (aq), but remember that it is not just a lone proton, but a proton chemically bonded to water (and with other water molecules via hydrogen bonding).

-Strong Acid: a substance that completely ionizes in aqueous solution to give H3O+ (aq) and an anion.

Example:

HCl (aq) + H2O (l) → H3O+ (aq) + Cl- (aq)
Hydrochloric acid donates a hydrogen to the water molecule to yield a hydronium ion. Hydrochloric acid thus increases the hydronium ion concentration of the solution and is considered an Arrhenius acid.

-Base: a substance that, when dissolved in water, increases the concentration of hydroxide ion, OH- (aq).

-Strong Base: a substance that completely ionizes in aqueous solution to give OH- and a cation.

-Weak Acids and Bases: are not completely ionized in solution and exist in reversible reaction with the corresponding ions.

Example:

NaOH (aq) → Na+ (aq) + OH- (aq)
Sodium hydroxide dissociates in water and increases the concentration of hydroxide ion. It is thus considered an Arrhenius base.

2. BrØnsted-Lowery Concept of Acids and Bases:

Independently, these two guys came up with a more flexible definition of acids and bases.

Acid: the species donating a proton in a proton-transfer reaction.

Base: the species accepting the proton in a proton-transfer reaction.

Example:

HCl (aq) + H2O (l) → H3O+ (aq) + Cl- (aq)
Hydrochloric acid donates a proton to water to yield H3O+, and water accepts a proton to become H3O+. So here, Hydrochloric acid is the acid and water is the base.

Example:

NH3 (aq) + H2O (l) → NH4+ (aq) + OH- (aq)
Ammonia accepts a proton from water to yield an ammonium ion and a hydroxide ion. So here, water is the acid, and ammonia is the base.

Conjugate Acid-Base Pair: consists of two species in an acid-base reaction, one acid and one base, that differ by the loss or gain of a proton. The acid of the pair is called the conjugate acid of the base, and the base is called the conjugate base of the acid. (ex: NH3 and NH4+, remember when you add the hydrogen to add one positive charge)


-Amphiprotic/Amphoteric Species: a species that can act as either an acid or a base (it can gain or lose a proton) depending on the other reaction. (ex: OH ← H2O → H3O+).

3. Lewis Concept of Acids and Bases:

Lewis Acid: a species that can form a covalent bond by accepting an electron pair from another species.

Lewis Base: a species that can form a covalent bond by donating an electron pair to another species.

Example:



Relative Strengths of Acids and Bases:


As seen in the above table, the strongest acids have the weakest conjugate bases, and the strongest bases have the weakest conjugate acids. This table can be used to predict the direction of an acid-base reaction: the normal direction of reaction is from the stronger acid and base to the weaker acid and base.

Molecular Structure and Acid Strength:

-The strength of an acid depends on how easily the proton, H+, is lost or removed from an H-X bond in the acid species. (ex: H-X = H-Cl, H-X = H-Br, etc.)

1) In going down a column of elements of the periodic table, the size of atom X increases (have more and more electrons), the H-X bond strength decreases, thus increases the strength of the acid.

Example: Group VIIA elements: HF, HCl, HBr, HI = HI > HBr > HCl > HF

2) Going across a row of elements of the periodic table, the electronegativity increases, the H-X bond polarity increases, and the acid strength increases.

3) An oxoacid has the structure H-O-Y- where the acidic H atom is always attached to an O atom, which, in turn, is attached to an atom Y. Other groups may be attached to Y.

-For a series of oxoacids of the same structure, differing only in the atom Y, the acid strength increases with the electronegativity of Y.

Example: HClO, HBrO, and HIO. Consider the electronegativities of Cl, Br, and I.
HClO > HBrO > HIO

4) For a series of oxoacids with the structure H-O-Y-On, with the same Y, more O's = higher acid strength.



5) The acid strength of a polyprotic acid and its anions decreases with increasing negative charge.

Example: H3PO4 > H2PO4- > HPO42- (the negative charge acts on the proton to hold it in tighter and make it less acidic).


Self Ionization of Water:

Self-Ionization/Autoionization: a reaction in which two like molecules react to give ions.

H2O (l) + H2O (l) ⇌ H3O+ (aq) + OH (aq)

Ion-Product Constant for Water: (a different version of Kc)

Kw = [H3O+][OH-] = 1.00 x 10-14 (at 25 degrees Celsius)
-Just like Kc, no units of measure
-Can be rearranged to find hydronium and hydroxide ion concentrations

[H3O+] = 1.00 x 10-14 / [OH-]
[OH-] = 1.00 x 10-14 / [H3O+]

Example:


What is the [OH-] for 0.150 M HCl in the following reaction?

HCl (aq) + H2O (l) → H3O+ (aq) + Cl- (aq)



We know the concentration of water is constant because it is a pure liquid, and we know that HCl dissociates completely (to 0M) because it is a strong acid.

So now we know the [H3O+] is 0.150 M, so:

[OH-] = 1.00 x 10-14 / 0.150M = 6.67 x 10-14 M

-In a neutral solution, [H3O+] = [OH-]
-In an acidic solution [H3O+] > [OH-]
-In a basic solution [H3O+] < [OH-]

The pH of a Solution:

-Defined as the negative logarithm of the molar hydronium ion concentration. (pH = percent hydrogen).

pH = -log [H3O+]
or
[H3O+] = 10-pH

(Note: it is possible for pH to be larger than 14 and less than 0, it's just very uncommon)

-The lower the pH, the more acidic; the higher the pH, the more basic. Can also be used with [OH-].

pOH = -log [OH-]
or
[OH-] = 10-pOH

Also:

pH + pOH = 14